寻找屏幕录像专家注册机

mdf3192078

各位大佬，在某处发现一张截图为屏幕录像专家注册机截图，其注册码为400位（不是常见的注册码），现在急需，求有注册机的大佬分享，感谢！！！

wl4592641

  外链:https://ang.lanzous.com/b04g57tuh      密码:d54g

gxb7427258

这个早就有了的吧，只是具体忘了是哪个版本了

PairsSoul

放弃这个想法吧

bob123

https://www.chinapyg.com/forum.php?mod=viewthread&tid=119276

那个注册机就是论坛大神们一起做的吧，无缘相见的。。还是直接用论坛的成品凑合下吧。

wgz001

PS的毫无痕迹啊

zxxiaopi

哈哈

不破不立

为什么非要鸡？论坛有可以用的版本，再不济就自己咔嚓

zyjsuper

不破不立 发表于 2020-7-4 09:53
为什么非要鸡？论坛有可以用的版本，再不济就自己咔嚓

之前友坛上别人发的。

[C++] 纯文本查看 复制代码

#include <iostream>
#include <Windows.h>
#include <time.h>
#include <cstring>

using namespace std;
int main()
{

	char st[21] = { 0 };						//用户名
	char jqm_a[31] = { 0 };						//机器码
	char jqm[21] = { 0 };						//机器码前20位

	cout << "请输入你的用户名：";
	cin >> st;
	cout << "请输入你的机器码:";
	cin >> jqm_a;
	int q;
	memcpy(jqm, jqm_a, 20);
	cout << "取机器码的前20位来算序列号" << jqm << endl;

	q = jqm[2];
	jqm[2] = jqm[18];
	jqm[18] = q;

	q = jqm[4];
	jqm[4] = jqm[15];
	jqm[15] = q;


	q = jqm[8];
	jqm[8] = jqm[11];
	jqm[11] = q;
	while (1)
	{
		char mb[7] = { 0 };						//运算的出的字符串
		int eax_3;
		int edi_3 = 0;
		for (int i = 0; i < 20; i++)
		{
			eax_3 = st[i] ^ jqm[i];
			eax_3 = eax_3 * i;
			eax_3 = eax_3 + edi_3;
			edi_3 = eax_3;
		}

		edi_3 = edi_3 + 0x3039;
		itoa(edi_3, mb, 10);					//mb=得到那5个秘钥字符，
		char str_z[51];							//存放真正的字符串


		char	str[51];				//序列号
		char	str1[6] = { 0 };			//序列号后5个字符
		int		esi = 0;
		int		eax = 0;
		int		ecx = 0;
		int		edi;
		int		arg_3 = 0x2D;			//序列号长度-5
		BYTE	dl;

		const char* str2 = "1234567890";

		int edi_33 = edi_3;
		srand((unsigned int)time(0));
		while (1)
		{
			for (int i = 0; i < 5; i++)				//生成序列号前10个字符
				itoa((mb[i] + 0x14 - 9 - (1 / 2 + i)), str_z + (i * 2), 10);


			for (int i = 0; i <= 9; i++)
				str[i] = str_z[i];
			int eax_4;
			int ecx_4;
			int edx_4;
			edi_3 = edi_33;
			edi_3 = edi_3 + 0x4d44;
			eax_4 = int(edi_3 * 3.14 * 0.1594896331738427110);

			edi_3 = eax_4;
			ecx_4 = 0x186a0;

			edx_4 = eax_4 % ecx_4;
			itoa((edx_4 % 10 + 0x41) - 9 - 11 / 2 + 9, str + 10, 10);

			for (int i = 12; i < 50; i++)
				str[i] = str2[rand() % 10];

			int g;										//交换
			g = str[2];
			str[2] = str[38];
			str[38] = g;

			g = str[4];
			str[4] = str[25];
			str[25] = g;

			g = str[9];
			str[9] = str[31];
			str[31] = g;





			for (int i = 0; i <= 4; i++)
				str1[i] = str[45 + i];
			esi = 0;
			eax = 0;
			ecx = 0;
			while (1)
			{
				if (ecx == 0xB26D)
				{
					edi = 0;
					while (edi < arg_3)
					{
						ecx++;
						dl = 0x80;
						do {
							BYTE ah;
							ah = WORD(eax) / 256;
							if (ah >= 0x80)
							{
								eax = eax + eax;
								WORD x = (WORD(eax) ^ 0x1021);
								eax = eax / 65536;
								eax = eax * 65536;
								eax = eax + x;
								ecx++;
							}
							else
								eax = eax + eax;
							ecx++;
							if (str[esi] & dl)
							{
								WORD x = (WORD(eax) ^ 0x1021);
								eax = eax / 65536;
								eax = eax * 65536;
								eax = x + eax;
							}
							dl = dl / 2;
						} while (dl != 0);
						esi++;
						edi++;
					}
				}
				ecx++;
				if (ecx >= 0x186A0)
					break;
			}
			if (WORD(eax) == atof(str1))
				break;
		}




		int g;											//生成第11,12个字符
		char str_1[41] = { 0 };
		for (int i = 0; i <= 40; i++)
			str_1[i] = str[i];

		g = str_1[2];
		str_1[2] = str_1[38];
		str_1[38] = g;

		g = str_1[4];
		str_1[4] = str_1[25];
		str_1[25] = g;

		g = str_1[9];
		str_1[9] = str_1[31];
		str_1[31] = g;



		char str_2[21] = { 0 };							//产生的那20个字符
		char str_3[3] = { 0 };
		int zj = 0;
		int edx_1 = 0;
		int ebx_1 = 0;
		int eax_1 = 0;
		for (int i = 0; i < 40; i = i + 2)
		{
			ebx_1++;
			str_3[0] = str_1[i];
			str_3[1] = str_1[i + 1];
			eax_1 = atof(str_3);
			edx_1 = ebx_1;
			edx_1 = edx_1 / 2;

			eax_1 = eax_1 + edx_1;
			eax_1 = eax_1 + 9;
			str_2[i / 2] = eax_1;
			ebx_1++;
		}


		int zjz = 0;
		for (int i = 0; i < 19; i++)
			zjz = zjz + str_2[i];

		zjz = zjz % 10;
		zjz = zjz + 0x30;



		if (str_2[19] == zjz || str_2[19] >= 0x41)
		{
			cout << "序列号为：";
			for (int i = 0; i <= 49; i++)
				cout << str[i];
			cout << endl;
			break;
		}

	}
	return 0;
}

zyjsuper

编译报错如下： 1>C:\Users\Administrator\source\repos\PmlxzjKeygen\PmlxzjKeygen\PmlxzjKeygen.cpp(84,4): error C4996: 'itoa': The POSIX name for this item is deprecated. Instead, use the ISO C and C++ conformant name: _itoa. See online help for details.

解决办法： 打开项目属性，点击C/C++ ——> 高级 ——> 禁用特定警告 ——> 编辑中加入4996

wl4592641

楼下！！！！！！！